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150=x^2
We move all terms to the left:
150-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+150=0
a = -1; b = 0; c = +150;
Δ = b2-4ac
Δ = 02-4·(-1)·150
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{6}}{2*-1}=\frac{0-10\sqrt{6}}{-2} =-\frac{10\sqrt{6}}{-2} =-\frac{5\sqrt{6}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{6}}{2*-1}=\frac{0+10\sqrt{6}}{-2} =\frac{10\sqrt{6}}{-2} =\frac{5\sqrt{6}}{-1} $
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